-2x^2-232x=-2520

Solution for -2x^2-232x=-2520 equation:

-2x^2-232x=-2520

We move all terms to the left:

-2x^2-232x-(-2520)=0

We add all the numbers together, and all the variables

-2x^2-232x+2520=0

a = -2; b = -232; c = +2520;
Δ = b2-4ac
Δ = -2322-4·(-2)·2520
Δ = 73984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{73984}=272$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-232)-272}{2*-2}=\frac{-40}{-4}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-232)+272}{2*-2}=\frac{504}{-4}
=-126
$